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Tuesday, November 4, 2014

LDO Regulator

3:15 PM
Recently the author had to adapt  a standard circuit configuration  (which often uses an npn bipolar) so as to operate as a low-dropout (LDO) regulator. The circuit shown here uses that rarity,  a depletion-mode MOSFET to implement the LDO function. What to do when you have to derive an analogue supply voltage  (close to +5 V) from an existing ‘digital’ 5-volt rail, ensuring sufficient decoupling between the two? One answer is  to step up and then use a linear regulator to step back down. However, if around 4.5 volts will suffice then an alternative is a home-made LDO regulator. The circuit is usually a fairly  standard shape typically a npn transistor (with base-current limiting resistor) is used.

LDO Regulator Circuit diagram:
 Regulator-Circuit


Initially, it would appear that this design suffices after all, the text books say the saturation voltage  is around 0.2 V. Unfortunately,  this is no longer true when the collector is tied directly to the positive supply. An enhancement-mode  MOSFET suffers  similar disadvantages: with the drain tied High you need greater than  drain  potential at the gate to achieve low RDS(on). Enter that seldom-used beast the depletion-mode MOSFET! Depletion-mode MOSFETS are ‘on’ even  when  V gs = 0,  and  you have to back-bias the gate  to achieve an increase in channel resistance.In the circuit shown the BSS139,  an NMOS depletion device, operates with the gate forward biased. With a load of 10 mA, the measured FET resistance was  38 ohms.



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